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Attempts 127

A 1.0-kg block on a table is given a push so that it slides along the table. If the block is accelerated at 6 m/s2, what was the force applied to the block?

  1. A
    0 N
  2. B
    3 N
  3. C
    6 N
  4. D
    The answer cannot be determined from the information given.

Topic Flashcards

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Question

Using Newton's second law, calculate the net force required to accelerate a 2.5-kg object at 4 m/s².

Answer

F_net = m * a = (2.5 kg) * (4 m/s²) = 10 N.

Question

In the original problem (1-kg block, 6 m/s² acceleration), if a kinetic friction force of 2 N opposed the motion, what was the magnitude of the initial push force?

Answer

The net force was 6 N (F_net = m*a). Net force = Push - Friction. Therefore, Push = F_net + Friction = 6 N + 2 N = 8 N.

Question

If the 1.0-kg block from the problem was on a frictionless surface and accelerated at 6 m/s², what can you conclude about the applied force?

Answer

On a frictionless surface, the applied force is the net force. Therefore, the applied force would be exactly 6 N.

Question

What would the acceleration of the 1.0-kg block be if the applied force from the push was 9 N, but a friction force of 3 N acted against it?

Answer

F_net = Applied Force - Friction = 9 N - 3 N = 6 N. Acceleration a = F_net / m = 6 N / 1 kg = 6 m/s².

Question

How much force is needed to give a 6.0 kg block the same acceleration (6 m/s²) as the 1.0 kg block in the original problem?

Answer

m * a = (6.0 kg) * (6 m/s²) = 36 N

Mini Quiz

1 / 3
In the original problem, does the 6 N force calculated necessarily equal the magnitude of the push, ignoring other forces like friction?
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