A 10-kg object moving at 5 m/s has an impulse acted on it causing the velocity to change to 15 m/s. What was the impulse that was applied to the object?

Question

A 10-kg object moving at 5 m/s has an impulse acted on it causing the velocity to change to 15 m/s. What was the impulse that was applied to the object??  
A. 10 kg·m/s  
B. 15 kg·m/s  
C. 20 kg·m/s  
D. 100 kg·m/s

Accepted Answer

Correct Answer: (D)100 kg·m/s. 
Rationale: The impulse applied to the 10-kg object equals 100 kg·m/s, calculated as the product of mass and velocity change (J = mΔv = 10 kg × 10 m/s). This impulse-momentum relationship quantifies the net effect of force acting over time to alter the object's motion from 5 m/s to 15 m/s.A) 10 kg·m/sThis equals the mass alone (10 kg) or the initial velocity alone (10 m/s difference misapplied). Correct impulse requires multiplying mass by velocity change: 10 kg × 10 m/s = 100 kg·m/s. This option underestimates impulse by omitting the essential multiplication step between mass and Δv.B) 15 kg·m/sThis matches the final velocity value but ignores both initial velocity and mass multiplication. Impulse depends on velocity change (15 − 5 = 10 m/s), not final velocity alone. Using final velocity without accounting for initial conditions and mass yields an incorrect result.C) 20 kg·m/sThis might result from adding initial and final velocities (5 + 15 = 20) then neglecting mass multiplication, or doubling the velocity change without proper scaling. Correct calculation requires mass times velocity difference: 10 kg × 10 m/s = 100 kg·m/s. This option misapplies arithmetic operations to the given values.D) 100 kg·m/sVelocity change Δv = 15 m/s − 5 m/s = 10 m/s. Impulse J = mΔv = 10 kg × 10 m/s = 100 kg·m/s. This calculation correctly implements the impulse-momentum theorem, recognizing that impulse equals the change in momentum when mass remains constant during the interaction.ConclusionImpulse quantifies momentum change through the product of mass and velocity difference. For a 10-kg object accelerating from 5 to 15 m/s, the 10 m/s velocity increase multiplied by mass yields 100 kg·m/s impulse, a value representing the net effect of whatever force acted over time to produce this motion change.

A 10-kg object moving at 5 m/s has an impulse acted on it causing the velocity to change to 15 m/s. What was the impulse that was applied to the object?

A
10 kg·m/s

B
15 kg·m/s

C
20 kg·m/s

D
100 kg·m/s

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A 10-kg object moving at 5 m/s has an impulse acted on it causing the velocity to change to 15 m/s. What was the impulse that was applied to the object?

A 10 kg·m/s B 15 kg·m/s C 20 kg·m/s D 100 kg·m/s

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Related Questions

A
10 kg·m/s

B
15 kg·m/s

C
20 kg·m/s

D
100 kg·m/s