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Attempts 127

A force of 12 kg stretches a spring 3 cm. How far will the spring stretch given a force of 30 kg?

  1. A
    6 cm
  2. B
    7.5 cm
  3. C
    9 cm
  4. D
    10.5 cm

Topic Flashcards

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Question

What physical law describes the relationship between the force applied to a spring and its resulting stretch?

Answer

Hooke's Law (The extension is directly proportional to the applied force, within the elastic limit).

Question

Using the initial condition (12 kg force → 3 cm stretch), calculate the spring constant (k) for this spring.

Answer

k = Force / Extension = 12 kg / 3 cm = 4 kg/cm.

Question

A spring stretches 3 cm under a 12 kg force. Under an 18 kg force, what would the stretch be?

Answer

Since extension is proportional to force, 18 kg is 1.5 times 12 kg, so the stretch is 1.5 × 3 cm = 4.5 cm.

Question

Write the formula for Hooke's Law that relates Force (F), spring constant (k), and extension (x).

Answer

F = k × x

Question

If the same spring from the problem stretches 10 cm, what force must be applied?

Answer

Using F = k × x and k = 4 kg/cm: Force = 4 kg/cm × 10 cm = 40 kg.

Mini Quiz

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Is the relationship between force and stretch for a spring linear (directly proportional) as described by Hooke's Law?
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