A 1,000-kg car drives at 10 m/s around a circle with a radius of 50 m. What is the centripetal acceleration of the car?
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A
2 m/s²
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B
4 m/s²
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C
5 m/s²
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D
10 m/s²
A 1,000-kg car traveling at 10 m/s around a 50-meter radius curve experiences a centripetal acceleration of 2 m/s².
This value arises from the kinematic relationship a_c = v² / r, which depends only on speed and radius, not mass.
A) 2 m/s²
Substituting into the formula gives a_c = (10 m/s)² / 50 m = 100 / 50 = 2 m/s². This moderate acceleration is typical for highway curves and reflects the inward pull required to maintain circular motion.
B) 4 m/s²
This would require either doubling the speed or halving the radius. It does not correspond to the given parameters and overestimates the acceleration.
C) 5 m/s²
This results from invalid operations such as dividing speed by radius (10 ÷ 2) or other arithmetic errors. It lacks foundation in circular motion physics.
D) 10 m/s²
This equals gravitational acceleration and would occur only at much higher speeds (approximately 22.4 m/s). It is inconsistent with the stated velocity and radius.
Conclusion
Centripetal acceleration is determined solely by speed and radius, yielding 2 m/s². The correct answer is A) 2 m/s².

Topic Flashcards
Click to FlipWhat is the formula for centripetal acceleration?
ac=v2/r,where v is the speed and r is the radius of the circular path.
In the given problem, what are the values of speed and radius?
Speed v = 10 m/s v=10m/s, radius r = 50 m r=50m.
How is centripetal force related to centripetal acceleration?
F c =m⋅a c , where m m is mass. Centripetal force is the net inward force required for circular motion.
Does the mass of the object affect the centripetal acceleration?
No, centripetal acceleration depends only on speed and radius. (Centripetal force, however, does depend on mass.)
What provides the centripetal force for a car turning on a flat road?
The friction between the tires and the road surface provides the centripetal force.