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The electrical force between two point charges is FEº. If the magnitude of both charges is doubled and the distance between them is doubled, what would be the new electrical force between the charges, FE ք ?

  1. A
    FE ք= FEº
  2. B
    FE ք = 2FEº
  3. C
    FE ք = 4FEº
  4. D
    FEº =FE ք

Topic Flashcards

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Question

According to Coulomb's Law, if the distance between two point charges is halved while the charges remain the same, how does the electrical force change?

Answer

The force increases by a factor of four. (Since F ∝ 1/r², halving *r* multiplies F by (1/(1/2)² = 4).

Question

If the magnitude of one charge is tripled and the other is halved, with the distance unchanged, what is the multiplicative factor for the new electrical force?

Answer

The new force is 1.5 times (or 3/2 of) the original force. (Since F ∝ q₁*q₂, the factor is 3 * (1/2) = 1.5).

Question

In the formula for Coulomb's Law (F = kq₁q₂ / r²), what does the constant *k* represent, and what are its typical units?

Answer

*k* is Coulomb's constant (≈ 8.99 x 10⁹ N·m²/C²). It relates the units of force, charge, and distance in the electrostatic system.

Question

Two charges exert a force F on each other. If the distance is tripled and both charges are also tripled, what is the new force in terms of F?

Answer

The new force is equal to F. (Factor from charges: 3 * 3 = 9. Factor from distance: 1/(3²) = 1/9. Combined: 9 * (1/9) = 1).

Question

State Coulomb's Law in words, describing the relationship between electrical force, the magnitudes of the charges, and the distance separating them

Answer

The electrical force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

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Does the electrical force between two point charges change if the sign (positive/negative) of both charges is flipped?
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