A 10 kg object changes velocity from 5 m/s to 15 m/s. What impulse was applied?
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A
10 kg⋅m/s
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B
15 kg⋅m/s
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C
20 kg⋅m/s
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D
100 kg⋅m/s
The impulse applied to the object is 100 kg·m/s.
Impulse is defined as the change in momentum of an object. Momentum depends on both mass and velocity, so impulse accounts for how much the velocity of an object changes as well as its mass. The relationship is given by:
impulse equals change in momentum, which equals mass multiplied by change in velocity
where m is the mass and change in velocity is the difference between final and initial velocity.
A) 10 kg·m/s
This value reflects only the mass of the object and ignores any change in velocity. Since impulse depends on how velocity changes, using mass alone does not give the correct result.
B) 15 kg·m/s
This option uses the final velocity rather than the change in velocity. Impulse depends on the difference between final and initial velocities, not just the final speed.
C) 20 kg·m/s
This value appears to be an arbitrary doubling of the mass or velocity change without applying the correct impulse relationship. It does not reflect the actual change in momentum.
D) 100 kg·m/s
The object’s velocity changes from 5 m per second to 15 m per second, giving a change in velocity of 10 m per second. Multiplying this by the mass gives:
change in momentum equals 10 kilograms multiplied by 10 meters per second
change in momentum equals 100 kilogram meters per second
This correctly represents the impulse applied to the object.
Conclusion
Impulse equals the change in momentum, which is mass multiplied by the change in velocity. For a 10 kg object whose velocity increases by 10 m per second, the impulse applied is 100 kg·m/s.
Topic Flashcards
Click to FlipState the Impulse-Momentum Theorem. What fundamental physics principle does it represent?
The theorem states that the impulse (J) applied to an object equals the change in its momentum (Δp). Mathematically, J = Δp = m*(v_f - v_i). It represents the application of Newton's Second Law over a time interval, showing how force acting over time changes motion.
Write the two equivalent formulas used to calculate impulse.
1. J = F_avg * Δt (Average force multiplied by time interval). 2. J = Δp = m * (v_f - v_i) (Change in momentum: mass times change in velocity).
A 5 kg cart is rolling at 2 m/s. You apply a force to stop it (v_f = 0 m/s). What impulse did you apply?
J = m*(v_f - v_i) = 5 kg * (0 - 2 m/s) = 5 kg * (-2 m/s) = -10 kg·m/s. The negative sign indicates the impulse is opposite the initial direction of motion.
Using the impulse-momentum theorem (J = F*Δt), explain how airbags in cars reduce injury during a crash.
In a collision, the change in momentum (Δp) of a passenger is fixed. An airbag increases the time (Δt) over which this change occurs. Since J = F*Δt = Δp, a larger Δt results in a smaller average force (F) on the passenger, reducing injury.
The unit for impulse is kg·m/s. Show that this unit is equivalent to the newton-second (N·s).
Since 1 N = 1 kg·m/s², then 1 N·s = 1 (kg·m/s²)·s = 1 kg·m/s. Therefore, kg·m/s and N·s are equivalent units.